What kind of sorcery is this?

Obviously it’s not sorcery; it’s all accountable with science.

(picture taken with floating camera)

LOL :smiley:

Captured with drone :smiley:

With voice or gesture command function.

Jerommel, do you think this magic can power the LED on this flashlight (i3s) if connected without the battery (of course I have to use some sort of dummy AAA)?

Asking this because the flashlight wont turn on with this 2V+ but when I use different i3s battery tube, the head is fine.

OMG Manker started producing batteries? Wonder though……what would be their 18650….prolly 10.5 volts or somthing

Probably not. Capacity is extremely limited. When you connect to head and try to switch on, you will get extreme voltage sag; it is not able to deliver power.
The driver does however recognise this voltage bump, so therefore it’s not working.

Amazing finding Jerommel! I’ve never thought of this before. Reminds me of Lemon battery back in my elementary grade

I think it’s probably because the impaired spring and tail connection won’t allow the needed current to pass through, there are salts between them (due to acid and metal chemical reaction).
You will probably measure very very low voltage when you put a load on it.
An analogue VU multimeter would probably read much less than 2.6 Volts due to that.

You’ll have to take out the spring and clean everything with soap and scrape off the mess and then re-assemble.

All modern volt meters, cheap or otherwise, have a very high input impedance. They can “see” a voltage thru very high resistances. As others have stated, and then reversed themselves, this volt meter is reading the boost voltage from the driver, even though there is no “connection”.
But actually there is, thru the voltmeter.

EDIT:
I base my assumptions on that it looks to me like the voltage reading is taken at the LED side of the light. The shirt clip is pointing down.
Even if that is the tail cap, I think the meter would still see the voltage thru the LED even though it is not on.

As Jerommel stated before, it is just a tube with a tailcap and Spring.
To identify by zooming the picture.
There is No led
Voltage reading is affected by acid from leakage.

I’m kind of curious as to how much current this accidental battery tube cell can produce. We’re probably talking microamps but it could potentially power a small joule thief, which would be kind of pointless but for some reason that’s still cool to me. Not sure which metals are somehow creating this reaction but over 1v seems pretty good, I mean I can’t think of any differing metal parts in there that would actually be aligned properly enough to create that much voltage. It has to be the spring and the aluminum right?

Have you checked the accuracy of your meter? How old are ITS batteries? I have found faulty meter probes to wreck all kinds of havoc on my readings, with both my Fluke and my cheaper Sears re-branded meter.

You’ve just discovered a use for lights damaged by alka-leaks; kudos!

And you’ve just infringed my patent for making free energy so be prepared to deal with my lawyers: Dewey, Cheatham, and Howe :stuck_out_tongue:

I’d have never thought about the alkaline voltage reaction still occurring here. I’m certain that there’s so little of it that it couldn’t power anything but a DMM checking voltage or an o’scope. Try it with an analog meter and it will probably read zero as those need more current to get a reading :wink:

Phil

i do not believe the ‘acid’ would make that much extra voltage
clean it out and remeasure
it isn;t acid anyway

there is a reason it is called an ‘alkaline’ battery

wle

Thats interesting… so the theory here is that there may be an electrolytic solution surrounding the spring and battery tube and thats creating the additional voltage potential. It would be really interesting to see a V measurement between the spring and battery tube.

(enter Mythbuster mode)

I think its plausible under the right chemical and physical conditions. Its like those kids science experiments using copper and Zinc pieces where you jab them into a potato, apple or lemon and measure a voltage potential from cathode to anode.

It is voltage were measuring, not amp-current. So while there could be a voltage difference, the available current may or may not be all that much.

Wouldn’t the spring NEED to be completely electrically isolated from the body tube though? If theres any conductivity between the two then its just a short… 0V, right?

Yep. Its here

Cool!!! Normally alkaline battery leaks piss me off. But this ones kind of cool. can you get a nail, screw or paperclip shove it in that rolled up paper and power the light?

[EDIT] doing that, as cool as it may be will probably tarnish the spring. and might ruin it.

clean it and remeasure
only way to know

wle