FW3A, a TLF/BLF EDC flashlight - SST-20 available, coupon codes public

Put me down for one! Thank you to the community who put this together.

Hopefully we’ll see a cottage industry spring up for things like SS or other bezels, different clips, maybe trit-capable tailcaps, or anything else the creative members here can think of.
Harder to do with lights where you might not have any way of contacting owners, but I imagine a quick post on BLF for exotic or durable bezels would get some serious interest.

Please add me to the interest list if it isn’t over.

I would like a code to order. Thanks!

Hey check out those photos neal posted on the last page. The clip ring doesn’t seem to protrude at all. Maybe it got the “it is fit” treatment too.

Interesting. Wasn’t the Rayleigh thing the whole reason the GT used a 4000K emitter instead of something with a higher CCT? I haven’t done a lot of thrower testing, but I thought that was the reason…

I hope at the very least it was an enjoyable exercise, even if it wasn’t any better than spending a few minutes playing Minesweeper.

Er, I enjoy little puzzles like that anyway. I doubt everyone does though.

Like, we were watching a sitcom one night and they posited a puzzle. So when the show was over, I went to go work out the answer. I ended up staying up too late because it was trickier than expected, but by golly, I finally found a solution.

FWIW, the puzzle was this:

  • You are presented with a set of twelve identical diamonds, each one extremely valuable. Same size, same shape, same color, everything. Except one of them is fake, and it weighs more or less than the others.
  • Along with these, you also have access to a balancing scale — the “scales of justice” type with two hanging platters, so it can only tell you which side weighs more.
  • If you can determine which one is fake, you get to keep them all. Otherwise, you keep none of the diamonds.
  • You can only determine the answer using the scale, and you can only use it three times.
  • You must decide exactly which three measurements to make in advance, before you have actually measured anything.
  • You don’t actually get to touch the goods. Someone else does the measurements and lets you see the result of each.
  • The diamonds will only be given to you if you can prove that your method always works. They won’t give you anything if you guess which one is fake but can’t provide a reliable algorithm.

So, how do you figure out which one is fake?

Oh, and then they add in one more detail: If you like, you can double your payout if you attempt the problem for thirteen diamonds — but in that case, getting a wrong answer will land you in jail. So there is a harder version for those who are willing to play with higher stakes. Everything is the same except there is one more real diamond in the set, and you can also use one dummy weight which has the same mass as a real diamond.

Any ideas?

Beginning on May 1st, there will be a 7-day long vacation in China.

:stuck_out_tongue:

I’d like to order one if I still can! Put me down for one.

In for 1

Definitely in for one if it’s not too late. Thanks!

In for one! Thank you

I would be interested in two

Oh man I’ve done this one before, but brain is failing me. Something like 1-4 vs 5-8, then one of those groups vs 9-12, then 1 and 2 vs 11 and 12 (those dependant on heavier/lighter).

Received coupon. Thank you!
Little drawback: 3$ more for standard shipping to Romania. But after all this waiting…
Ordered! :slight_smile:

I’d use my UV convoy s2+ to find the fake. Swallow the diamonds, beat the captors with the provided scale. I think that’s the right answer.

Thank you goshdogit, that would be them!! :+1:

I had a similar idea. Break them into three groups of four but then got confused about where to go after you compare the three groups against one another without running out of tries. Hmmmmmmm.

Yeah, not at my desk at the moment to work it out again, but I’ve definitely worked it out before in a repeatable fashion.

I do like the idea of the 365nm and violence though ;p

WARNING FOR RIDDLE ANSWER ATTEMPT

I’m pretty sure this works, but I’m tired so I may have missed something. It also doesn’t seem like the most efficient solution, which is worrying.

-Scale 1—————Scale 2———-Aside

1,2,3,4,5,———–7,8,9,10,12——6,11,13

1,3,7,9,11———–2,4,6,8,10——–5,12,13

1,2,7,8—————3,4,9,10———–13

This should result in the following mapping, where L: left side is light, R: right side is light, and B: the two are perfectly balanced (as all things should be).

1 LLL
2 LRL
3 LLR
4 LRR
5 LBB
6 BRB
7 RLL
8 RRL
9 RLR
10 RRR
11 BLB
12 RBB
13 BBB

I’m interested in ordering one if it’s not too late. Thanks!