4.2V means that the cells are acting in parallel? so the 1000 lumens are the product of high current draw. 3 cells in parallel can provide 3x the amperage of a single cell. So what's the lumens output on 3x Eneloop?. I would guess 300lm.
On second thought, maybe the spec is wrong and it’s a boost driver. That would be a strange choice sine it’s less efficient, perhaps less performance for almost no gain when compared to sharing circuit with lithium light, though still same capacity. Would be interesting since it might work with 3 14500’s in that case. The american education system was never that great anyway.
It wouldn’t in theory, but in practice it might since it’s going to use a boost driver (like a giant AA light) and powerful/cheap 1.5v boost drivers are rare. Kreisler’s reasoning is wrong, though, since voltage is interchangeable with current given same capacity/power.
This arrangement would be more convenient with a 4x setup like the king. I mean, who sells aa’s or 14500’s in 3 packs?
The cells in the Rook are obviously run in parallel. If it takes AA cells then it MUST have a boost circuit which means, unless it goes DD on 14500 cells, output will suck on 14500s.
i am guessing only. the driver contact disc reminds of similar lights with parallel cells. in series, 3 x 4.2V = 12.0V. The specs state 3-4.2V and i dont believe that this budget light has a fancy 4Sevens-like buck-boost-driver.
education. somehow i still think that all dogs are boys and all cats are girls :D
It should be fairly powerful on 14500 regardless of whether DD or boost/buck (unlikely since $:money_mouth_face:. The real question is how it does on AA. The most powerful AA light I have is the Trustfire 3T6 with 4 batteries in the 3x18650 config. Draws 4+A.
Sounds like it would have been better to just leave it at a 14500 light and not waste the time to have it 3AA. If it were four AA in series, I would be interested, but then it couldn't be done with 14500's too.
Seems like a boost driver is going to be inefficient or get hot?