Anyone know how to calculate 50ua parasidic drain?

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pounder
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Anyone know how to calculate 50ua parasidic drain?

It’s from 2 18650s..just trying to figure out how long it would be before te batteries died..they’re 2500ma..thanks

Old Eyes need Light
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[quote=RecycledElectrons]

50uA is 50 micro-amps. That’s ( 50 / 1,000,000 ) Amps = 0.00002 Amps.

You may have slipped a cog; I do frequently Sad

I make it 50,000 hours – or about the span for an LED.

With two cells, should this double?

EDIT: Sorry, I only took in the first & last lines. You already had the 5.7 years Smile

PilotPTK
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Old Eyes need Light wrote:
With two cells, should this double?

Depends if they’re in series (no) or parallel (yes)

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pounder
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cool thanks for the info..but do 2 2500ma cells in series cells not represent as 5000ma? 5.7 years is plenty enough but just wondering

Electroman187
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No, 2 cells in series does not double the capacity.

Rufusbduck
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Series doubles the voltage, parallel doubles the Ah.

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pounder
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ahh thanks for the explanation..makes sense

Mr_Krabs
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The parasitic drain is probably less than the self discharge of the li-ion cell. So don’t expect 5.7 years. Li-ion’s tend to die within two years when sitting by themselves.

pounder
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Mr_Krabs wrote:
The parasitic drain is probably less than the self discharge of the li-ion cell. So don’t expect 5.7 years. Li-ion’s tend to die within two years when sitting by themselves.

yeah I was just wondering if it was as bad as my h2 headlamp which dies in 3-5 days..I use this light so it’s all good..