Getting a bit confused here to say the least lol. So I would connect them together in parallel preferably?
Maybe 5 is enough?
Yea basically but remember these are 6 volts LEDs so you need 2 batteries in series to make the 6 volt led work and 2 batteries in parallel.
The drivers will be connected in parallel if using more then one.
Amperage wise from the driver you want at least 15 amps. In a parallel circuit each led will receive 5 amps. So for the 3 the total 15 amps. That may give you around 12000- 13000 lumens.
that’s whatbI mean, it comes in 2s2p configuration from factory.
So then it gets 6v+. And all in parallel to achieve 5 ish A.
But is one driver enough, or do ai need 3?
what? huh?
If you are using the the 5 amp drivers you will need 3 to get 15 amps. And some panadol lol
I bet a major headache.
Maybe you travel to Finland, and do it for me eh?
And I’m studying to become an electrician. I had a hard time understanding lol. Don’t look good for me huh?
Just go with a fet or mod the current driver first. You can buy resistors for cheap. It’s easy to do it just get confusing to talk about lol.
Yeah will have to sleep on it!
What a soup huh? We all talked at the same time?
Hahaha yea. usually I’m half on here and playing battlefield at the same time lol
This seems the easiest route and you can then report to us on your results. I don't think anyone here has tried it yet. You don't have to remove the stock resistors. Just stack additional resistors on top to lower resistance. I prefer to solder a wire to each end the bank and then swap resistors at the wire ends. Much easier and less heat stress to the driver.
Just took a look on the driver .
It seems that it has different sense resistors (to control current) for every LED .
^
I haven't opened my wifes 4S MT03 yet, but one of the reviewers posted pics of the 2S2P driver and it had 3 separate buck drivers (one for each LED). So, yes, there should be 3 different banks. I would expect them to all have the same resistors values in each one.
Yea my driver pic is on the first pages of this threads it appears to have 2 R100 sense resistors per led? I could be wrong I’ll have to open it again and have a look.
Exactly .
It has 2 x R100 in parallel for every led . So total resistance is 50 mΩ . Adding another one will drop resistance to 33.33 mΩ .
I will have to try it today or tomorrow .
I thought adding resistors, made the resitance higher thus lower current? I forgot how it goes.
Resistors work like restriction,more ohms, less current, less ohms more current? right? So how can adding resistors lower the resistance? Unless you put a smaller resistor on top of the other?
The smaller ones or the big grey 100 boxes?