DC to DC buck converter circuit question

I have bought a stanley hid 0109( used off ebay), a Makita LXLM01W 18v LXT, and a LM2596 DC-DC Buck Converter with the intention of combining the 3 -eliminating the sealed lead acid batterys in the 109 and running off my 18 volt makita lxt battery packs. The lm 2596 converter is good for 3 amps output which might be enough for holding on the 109 but not enough for starting current which apparently can get up to 20 amps. I was wondering if I could add a capacitor or something to deal with the starting current and if I could parallel 2 of the converters if need be.

3A???
I think you are dreaming.

Well what would a 35 watt hid pull? 12 volt x 3 amp = 36 watts

Why do you think he is dreaming :quest: Please explain what you mean!

Connecting two circuits in parallel won’t work. Adding large output capacitor might help but crucial thing is for how long hid draws much greater current. If that time is very short you might get away with large low esr capacitor…

These LM2596 DC-DC Buck Converter can’t handle 3 A continuous current at these voltages.

I just run across this information 35/50/55 watt HIDs so apparently I will have to have 4 amps holding with a way to deal with 15 amps startup. Any ideas?