Hello boys.
I have bought the driver P2500 20mm 3V-9V 1 or 2 cells 2800mA Buck Driver Board (1 PC) from Kaidomain. http://kaidomain.com/P2500-20mm-3V-9V-2800mA-Buck-Driver-Board?search=P2500%2020mm%203V-9V%201%20or%202%20cells%202800mA. There is written:“Input Voltage: 3V - 9V (1 / 2 x Li-ion)” and “Feature(s): When the voltage is below 2.7V, LED will shut down automatically to prevent the destruction of the battery.” But the cut off on 2,7V is only useful for 1 Li-ion cell 3,7V. If you use 2 Li-ion cells (7,4V together), the cut off should be 5,4V, should not it? I am going to use 2 cells, so my question is: “How is it possible to increase the cut off voltage to 5,4V on the board this driver? What parts is needed to exchange?” Can anyboby help me?
Thank you.
Regards.
Miloslav, Czech Republic, Europe
It probably does even though they do not state it in the product description. Could be 5.4V or 5.8V with a flash. But it might not have the protection for 2 cells, only for single cell use. I have some of their similar BD39 drivers and the LVP for 2 cells varies by model/current. I think it was the 2.2A (maybe the 1.5A) that only offered 2-cell LVP in one mode offering but not the others…had to be sure I chose that one when I purchased.
I would message them to ask and they should be able to confirm for you. They can be slow to reply. You could also message BanL here on the forum…if he sees that he’ll have the correct information. https://budgetlightforum.com/user/14720
I don’t know about modifying the circuit that way…might be possible.
I have written to Kaidomain, whether it is possible to increace the cut off of that driver to 5.4V, but I got no answer by today. So I will try it on my own or leave it be.
It is possible that the cutoff becomes 5.4V once the voltage exceeds a certain amount.
No way. By the “P2500 20mm 3V-9V 1 or 2 cells 2800mA Buck Driver Board” the cut off is always 2.7V. I have measured it.