If the resting voltage is 9.68 volts like the op stated above what use is it. If he sticks it in a flashlight it could fry his driver or give to much current from the higher voltage and go “POOF”.
I=V/R
His over twice the normal voltage. You might try removing the PCB but I don’t think the circuit can boost twice the voltage. Far as I know it’s just a simple controlled FET switch.