A month or so ago I ordered a Haikelite HK90S with the intent of modding it, since it could handle bigger (9090) LED’s and has a FET driver so in theory it should be able to push a powerfull LED quite hard.
Today I removed the driver, mainly because I wanted to replace the very thin (22AWG) wires that Haikelite used, but after I was finally able to remove the driver (it was ‘glued’ in place), I noticed a couple of things that raised some questions (for me).
So I decided to take photos of the driver and to dedicate a topic to it.
First of all a general overview of the driver:
A ‘close up’ of the charging SoC IC:
But here is the part/section of the driver that raises a few questions to, given my lack of (enough) knowledge:
As you can see in the photos above, it uses an Infineon (real/fake?) BSC010NE2LS MOSFET, but to the left of it there is an unoccupied pad, which, as far as I can tell, could also house a Mosfet.
My question now is: Would it be worth it (and would it work) if I place a second MOSFET there, given that the whole purpose of this flashlight is to mod it and put a more powerfull LED in it?
(I would probably swap out the current FET and install 2 brand new, matching ones.)
That brings me to my second question:
As you can see in the photo below (and probably already noticed in the photos above), Haikelite did some really “Creative Soldering” on the driver, next to the MOSFET(s):
What is the specific purpose/goal of this horrible and ugly solder blob?
The R18 and R17 markings above it, indicate to me that it originally was intended for 2 resistors, but I assume the bridged the pads by use of that solder blob.
Does it relate to the unoccupied/unused MOSFET pad/slot?
(In that case I assume that, if it is worth placing a second FET, I have to remove the solder bridge and place the correct resistors on R17 and R18.)




