Hi,
Unfortunately, the new diodes were too large, like WAY too large. Maybe twice the length and twice the width of the original one.
So question: If I got another SS34, I don’t understand why I couldn’t stack them on top of the original SS34? I guess that the individual diodes might have slightly different V vs. I curves or something, but wouldn’t current split essentially evenly between/among the paralleled diodes?
PRE-EDIT: NVM - found this: http://electronics.stackexchange.com/questions/6151/is-paralleling-diodes-a-bad-idea
So, it looks like even stacking 2 SS34s would not be a good idea, so I’d have to find another schottky diode that was the same package/form factor as the SS34 but with higher current rating…
While I was down in my “lab” and scratching my head about the new diode, I started doing some ohming around. I didn’t complete the job, it’s just tedious, but (don’t laugh) here’s a pic of what I was able to trace:
The small “BRN” is that component just to the left of the (original) R200 resistor.
The 6-pin chip on the left is the unmarked 6 pin chip.
I wasn’t able to find anything connected to the upper-left pin of the top A0EC/AOEC chip.
I’m not sure where to go with this from here. I kind of think that I’d be ok running this with an R100 stacked on top of the R200, maybe if I put some thermal putty around the driver (recall that I haven’t tried this in an actual light with an actual battery or batteries yet). Maybe it might even be worth risking one driver to try it, even without any heatsinking of the driver? I don’t know…
EDIT: BTW, I posted a spreadsheet with the in vs. out voltage/current earlier:
https://budgetlightforum.com/t/-/27544?page=2#comment-620633
Was that the info that you all were looking for?