The resistors at the head are bleed resistors and have zero to do with current to the LED. They simply allow positive voltage to “bleed” (leak) into the body so it gets back to the tail where the driver is.

On the driver R14 is a simple gate resistor for the FET and also has zero to do with current.

If you just want to experiment you can swap the FET it’s self for a more capable one (say IRLML2502) but I didnt spec the stock D181C, it may be plenty good enough that even a top tier SOT-23-3 FET (such as the mentioned IRLML2502) won’t increase real world performance any.

Best bet is to use it how it is and wait for me to finish my BLF based driver. I’m waiting on boards now…