Is it posible to remove 2 or more 7135 chips in a 7135*8 Convoy S2+ in order to decrease output?
Yes. I do this all the time to decrease current output on these drivers. A little bit of flux across the three pins and heat with a hot soldering iron with a little solder on the tip and it should come straight off.
Like said above, its really an easy task. Ignore the big connection in the back; its contiguous with the center pin in the group of 3. So just heat those three for a second, pressing slightly toward the chip with your iron and it’ll just pop right off of there.
Thanks. Does it matter the position of the chip to remove? I mean, if I am going to remove two chips, can i choose both randomly?
Yes, you can choose both randomly, not matter the position…
Thanks again
I use my rework station to remove them. About 270° C, low air, and smallest nozzle, they come right off. Also use same method for putting them on.
This thread answered a question for me. Thanks
The 7135’s are all in parallel - that’s why it doesn’t matter which ones you remove. This is a big reason why we love these drivers - easy to mod for controlling output, or rather amps getting to the LED, which effects output O:-)
In the case of this Qlite driver discussed on this thread, it’s true that all the 7135s are in parallel and any can be removed (or stacked) to control output. But just in case someone else comes along with a different driver, I just wanted to point out that this isn’t always the case. Some drivers have certain chip locations that have a specific function, like controlling moonlight. You wouldn’t want to remove or stack on those.
Thanks for the info. I just removed 2 chips from a 4x7135 Convoy S2+
Leaving 2 chips gave me 12-99-240 lumens do you know if going to 1 chip will cut these in half ?
My S3 is somewhere around 22 –225-540 lumens with 4 chips. Close to what the S2+ started with.
useful thread, thank you…