Yet I'm not really getting this..

So, basically, an ideal reflector would reflect a point situated in the focal plane at an angle, that angle being the 90 degrees perpendicular to the emitter plane, let's disregard that for now, our emitter it's an ideal point in space.. and it will do that for every point on it's surface area - Now that would result, ideally in a hot-spot the size of the reflector, am I right ? And that would be from a single point, our ideal emitter. So in a real application, where our emitter would be more or less a plane itself, all but one point in the center of the plane would be in perfect focus and give us most of the hot-spot ? Sounds too ineffective.. and the rest of 99.999.. % of the emitter would be reflected as the corona.. ?

What I was thinking was that the emitter surface area would give the shape and size of the hot-spot - let's say the focal point in the emitter's plane it's reflected in a point somewhere in front of the reflector (focal distance ?) and whatever else surrounds it, the rest of the emitter area just gets more and more offset in a linear manner ? Thus giving us a bigger hot-spot for a bigger emitter ? Thing that can be confirmed in practice ? So, from that slide, what I'm taking as the divergent angle/s from the various points on the surface of the reflector it's basically what would form the hot-spot shape - also with distance, the hot-spot gets bigger, which makes sense.

It's just, I can't imagine a single point in the emitter surface to basically give us the bulk of the hot-spot, while 99.999.. % of the rest of the emission area would be in the corona and spill. And I still don't get how the corona is formed.. :))