If you believe you know something, why not post it, instead of you silly antics.
Since you do not post the answers, it must be you that do not know why (If you know why it is “silly antics” from you).
What is up HKJ?
It’s quite unfortunate that gauss163 does not contribute to this topic. It really does look like he just wants to attack you.
Scientists do not attack pseudo science.
Scientists conduct science (so why aren’t you sharing your thoughts about this topic?)
HKJ is not a pseudo scientist because he does not answer your questions.
Following protocols is part of science. Following protocols is not the same as “simply blindly following” something.
While no-load voltage is needed to estimate the remaining capacity, voltage under load would still be useful information, as it relates to the battery’s performance under load. Voltage sag is often talked about when comparing similar batteries, and lower voltage sag is one of the reasons people prefer the Sony VTC6 over the Samsung 30Q, and the 30Q over the LG HG2. But people always talk about it in a general sense, without much in the way of data to back it up.
I have no idea how you would collect or display the data, but hard information about the voltage under, say, 5, 10, 15, and 20A loads would be useful for comparing similar batteries, particularly high drain batteries intended for demanding applications.
HKJ already does all that in his reviews.
A lot of Gaussian noise in this thread… 
But i’m confused right now.
I always look at the discharge curves, which i assume are V/t diagrams (or rather V/Ah diagrams) made of measurements under load.
Or did i miss something?
Only who is doing the posts.
Information level will increase when gauss163 leaves, he has something against posting knowledge. He probably believes it is better for you to spend a couple of hours searching for information, than it is if he post it.
That’s how I interpreted them too.
Again: scientists do not attack pseudo science. Scientists do not teach the general public; scientists conduct science and publish their findings. For example teachers teach the general public. Scientists do not need extreme patience and thick skin for debunking popular pseudo science. That is because it is not their job to do so. Again, a teacher for example could need extreme patience and thick skin to teach a class.
So basically you do not understand the role of a scientist.
Oh no gauss163 I’m not misunderstanding! It is not up to HKJ to give you any scientific proof that Alkaline cells must be tested under load! It is not up to HKJ to shed any light on the underlying science governing the matter.
gauss163, it looks like your background is not science, as you’re making a lot of false statements. Nevertheless you accuse HKJ’s work as pseudo science.
This is how it’s done in science:
You accuse HKJ of pseudo science as you severely imply, then you deliver the unambiguous evidence it is so. It is certainly not up to HKJ to answer your questions.
If you try to enlighten me you hide it very well.
I do generally not count snide remarks or “use google” as enlightenment.
Guys….
Let’s give it all a rest for now.
Start over next time, without the attitude, anger and frustration. (you know who you are)
This sucks.
Not many and many of the links you posted where behind paywalls. You also posted links that was only google searches.
What you obvious never understood was that just because a scientist succeed in fast charging a battery, it is not the same as every charger on the market can ignore the manufacturer specification for all batteries and fast charge them.
What I post is usual backed by research and often done by me.
I do not see any reason to explain anything to you, you have never posted any research you have done, but you frequently complain about my postings, without showing any research against it.
Follow-up question: Can voltage under load be measured in a flashlight? Another words, using the flashlight and its LED as an alternative to a resistor?
Yes. How easy it is depends on your light. The Olight S1R ( and a few other similar lights) bring the battery voltage to the outside of the light. This makes it very easy. I did some test on my light / battery, see this post
Thanks. One question about this: when measuring voltage under load in a flashlight, I do not see the LED light up, so where is all the energy going? What is absorbing it if there is no dedicated resistor?
Measuring voltage of a li-ion is only a estimate of what capacity is in the battery unless you have already collected data on the particular cell you are using. li-ion’s usually dont have the same discharge curve. You can take two li-ion’s of a different make and compare them in HJK’s graph’s. Say a Sony US18650VTC6 at a 5 amp load, cell voltage at half capacity is around 3.65v. Compare a NCR18650A, at the same 5 amp load half capacity is 3.25v a .4v difference. Using HKJ’s graph’s has data to improve the guessing of your capacity of a cell. Even resting voltages vary between cells, that’s why it has always been considered a estimate.
I don’t know what your test setup is so I can not provide helpful advice except this - if your intent was the flashlight be the load for your battery, and the LED is not producing light, it is not loading the battery, and you are not measuring the battery voltage under load.
In my test, the battery voltage is accessible via the contacts. this review shows the tailcap about 2/3 of the way down the page.
I am using a Convoy S2+ with the tail cap removed. I press one DMM probe against the back of the battery and the other DMM probe against unpainted surface of the flashlight tube. I get 3.67 Volt this way.
When I measure voltage of the battery at rest (outside of flashlight), I get 3.74V.
My guess is what I’m doing is not the correct way to measure voltage under load in a flashlight, and that’s why the LED does not come on, but why am I seeing some voltage drop then?
Your meter connected in series with the battery is not an appropriate way to measure the battery voltage. I can not counsel you how to go about measuring the battery voltage under load with that flashlight.
I suspect you are seeing the voltage drop due to a small current flowing through the light and your meter.