Hi, I saw some manufacturers bundling protected high drain batteries with their flashlights. Can someone explain how these are supposed to work? Up to now my understanding was that due to high current delivered by IMR cells, this limited the possibility to add the protective circuitry, so high drains were always unprotected. My second question is whether there is any current level, from which the batteries are considered high drain?
Link us to the cells in question or do you know the manufacturer or anything? Sounds like it’s typical uninformed seller looking for uninformed buyer BS…
I’d consider anything more than 2C discharge rate to be “high drain”.
Protective circuit with 10-15A using very low resistance MOSFETs and IMR cell
Klarus 3100mAh for example
Klarus 3100mAh - this is precisely the one I meant. So if im getting it right, this is principally a lower current IMR battery with protective PCB added. I wonder if something like this would be possible with a high, 20+ Amps IMR cells? What prevents the protective PCBs from working on such batteries?
Physical size restraints. All of the components in the protection circuit are able to be sized up no problem, bigger FET’s, higher power resistors. It’s the fact all components, the PCB, and all connections need to fit in the same sized space as the cell it’s self that limits it to tiny iC’s and parts that limit current so much.