Ha ha. I knew it would be XML. I had some DX points, so I paid maybe $2 less than yours. I’ll contact DX anyway, and see if I can score some free points or something. Love the light though. I can’t decide whether to eat the expense of swapping XM-L2, or reflowing the XMLs on Noctigons.
I’ve got too many mods on the go, it’ll have to wait.
I used a 2$ coupon code when I bought mine. :p :D
Maybe ill get it done next month. No time to start on it now. Cant do that much either. I have some parts incoming from various places. Still not decided exactly on what do do with it in terms of switch type.
Tried with these yet? https://www.akkuteile.de/keeppower-imr26650-4200mah-50a-3-7v-li-ion-akku/a-12036/
Keepower doesn’t make cells so better to find out what’s under the wrapper.
With a direct drive driver you DO NOT multiply anything by the number of cells. Amps in is amps out. It is 13 amps, and 13 amps is 13 amps, there's no way for that kind of circuit to end up with anything being at 39A.
3 cells, yes. And 3 sets of LEDs. Each series string of LEDs has its own cell. The tail current is divided by the number of LEDs (or in this case, the number of series strings in parallel). That's 4.3A per string of 3 LEDs.
CONVERT TO WATTS on a setup like this if you want to see what's really going on! To get a true number you need to know both the input (tailcap) amps and the input voltage. Using a Vin figure of 4.2v per cell will throw things off, as they aren't going to be anywhere near 4.2v while delivering 13A. Make a guess of 3.8v per cell under load, that's 11.4v input, and 13A input. 11.4 x 13 = 148.2 watts.
Now if you're just using that '39A' number as a way to put the output in terms of a single LED powered by a single cell, or LEDs in parallel with cells in parallel, yes, this 148W setup would be the equivalent of 4.3A per LED, with 9 LEDs in parallel, and an input voltage of ~4.2v = 39A, but that's a clumsy way to do it. Convert to watts instead. It is an actual number and not something that involves guessing.
Have you been away Comfy? I was hoping you’d pop by when I started this thread. I was surprised when you didn’t show up and rap my fingers with a ruler.
Okay. Each string is seeing 4.3A, so is each emitter in the series string seeing 4.3A, or is each emitter only seeing 1.4A?
I know Im wearing your patience thin, but it takes time for things to soak into my brain. I guess I should start learning about watts. I’m lost when people start talking watts in terms of flashlight output.
In series, they all see the same amperage.
Converting to watts is useful because the wiring configuration doesn't matter. Watts is watts is watts. Three LEDs in series, fed 3 amps at 9 volts, is 27 watts. Three LEDs in parallel, fed 9 amps at 3 volts, is 27 watts. Isn't that easier? :)
Well…yeah., but now I have to learn new math.
Amps times volts equals watts. Watts divided by amps equals volts. Watts divided by volts equals amps.
So if I take a tail reading and see 5A and 11V I’ve got 55 watts?
Yessir. It's useful because it's not dependent on the circuit layout to be a useful comparison to some other completely different circuit. You can convert backwards from the watt number if you'd like, as in your light is the same light output as if you had 9 LEDs in parallel running at 39A total/4.3A per LED @ 3.8-4.2v input (but no part of your light is actually doing 39 amps anywhere). The math works the same either way. A given power level (watts) gives the same light output, no matter how that power level is achieved.
3v or 6V emitter doesn’t matter?
Well, the numbers you multiply to get the watts matters. I mean, you can't use 3v in your math if your LED or input voltage isn't 3v.
Your series strings of 3 LEDs each are, as it appears to the driver, a single LED with a forward voltage of around 11.1 volts. 4.3 amps per string, at 11.1 volts, is 48 watts per string, times 3 strings in parallel, for a total of 143-144 watts (this is the theoretical output power from the driver; the difference between the input watts and output watts is the driver efficiency). Doesn't matter how you break it down or how many steps you use to get there, watts is watts.
wrt the post above: 11.1V x 4.3A = 48W per string or 48/3 =16W per emitter.
For those who fumbled through the math, I’ll try to summerise:
Tailcap reading = 13A
3x cells in series under load about =3.8x3 =11.4 V ( in series, current is the same, voltage adds up) [ input power is 13A×11.4V = 148 W ]
LED configuration is 3S3P ie, 3LEDs in series (one string) in parallel with two other strings.
All three strings receives13A of current so each string receives 13A/3 =4.3A. Remember, in series, current is the same while voltage adds up so each LED in a string (same for each of the three strings) receives 4.3A of current.
ASSUMING 100% efficiency, power in= power out so power out would be 148W and approx power per LED would be 148W/9= 16.44W…
Ouchyfoot, If it were a 12LED light with four strings of 3xLEDs and a current draw of 15A, tell me the approx current per LED. 
Oh oh. Is this a trick question? Nobody said there was going to be a test!
I would approximate 5A per emitter.
About 3.75A. Each string of three LEDs gets approximately the same current. (Small differences possible due to total Vf and other minor differences) therefore current per string (four strings) =15/4= 3.75A and since each series LED in a string has the same current passing through it, current per LED is 3.75A
My mistake. Four strings. I was distracted during the test.
Lol.
You all are nuts.
Speaking of which, I need to do this mod to my TR-9xT6 some day.