Hey thanks for the update. Does the battery carrier limiting the current on eneloop?
as for the FT nanjg driver you pointed out, I have using quite a lot of it. perform like it should be although it’s not like Qlite on IOS one.

The total current draw with Nimh batteries on high is about 2.1A and this is also measured by other forum members. The AA batteries are in series so 2.1/3=0.7A current drawn from each battery. I’ve never measured the resistance of the battery carrier though but I think it won’t be an issue to limit just 0.7A current draw from each AA battery.

If the batteries are in series 2,1A is drawn from each battery. (if the batteries are parallell they would be delivering 0,7A, but then you would have a voltage of 1,2V instead of 3,6V…)

i did a basic test some weeks ago with my X3 from wallbuys. I used 3 quite fresh GP recyko’s and measured 4,02V resting voltage at the battery carrier. Then i used 2 DMM, one measuring current (i think it was about 2,8A on high) and one measuring voltage under load.
-It didn’t take long for the 3 batteries in series to fall to 3,2V under load.
-So i guess that’s why i have been having problems with this flashlight when running it on high with AA’s. After a while on high it starts ramping up and down, and i’ve been wondering if that’s a low voltage warning.
-Maybe recyko’s don’t keep up their voltage under load as good as they would have needed to be used in this flashlight.

i’m going to gift this flashlight, so i’m thinking about changing driver to something easier on the batteries, maybe 1400 mA could be good enough for this flashlight in the hands of a non-flashaholic using it on AA batteries.

if you test parallel, it would be 2.1 each battery

no, when you add them in series the current drawn from each battery is the same, but the voltage adds up.
so for the total of 3 batteries @ 3,6V and 2,8A every battery needs to deliver 2,8A and 1,2V

power = 3,6V * 2,8A => 10,08W
each battery provides a third of that:
1,2V * 2,8A = 3,36W

Hi OscarM, I think what you mean are on the output side? Let’s say a light with three LED wired in series, the current going through them is the same but the voltage is added up.

EDIT: Okay I am not an electronic guy so I don’t want to put it into calculations in case my math errors may confuse some people. So I just mention an example:

My friend has a Skyray STL-V2, as we all know it has a single XM-L powered by 2*18650 in series. With freshly charged batteries we measured about 1.4A and 8.2V at the tail, but actually the LED receives about 3.5V and 2.8A of current.

no! we are talking about current draw! not about mAh capacity!

hey, cool down and think a little?
yes, we’re talking about current draw, and i included voltage and power as well.
noone has talked about capacity… (power (W) and capacity (mAh) is not the same thing)

-if you have 3 nimh AA batteries in series, you get (nominal) 3,6 V. agree?
-if those 3 batteries in series are in a flashlight that pulls 2,8A we have 3,6V and 2,8A from the batteries. agree?
-the power from the batteries is 3,6*2,8 = 10,08 W. agree?
-for 3 batteries to reach 10,08W, each battery need to deliver a third of the total power: 10,08/3 = 3,36W. agree?
-each battery has a voltage of 1,2V nominal, and to get the current when we know the power and the voltage we take divide the power by the voltage: 3,36/1,2 = 2,8.

So in series each battery has the same current drawn as the total current draw. the benefit of adding batteries in series is that you get a higher voltage.

Guys, OscarM is correct as in the formula. reference here.
So, if one buy this light merely to use with AA only to obtain maximum output (and also run time), do you guys as users recommend it?

Guys, OscarM is correct as in the formula. reference here.
So, if one buy this light merely to use with AA only to obtain maximum output (and also run time), do you guys as users recommend it?

Ok sorry guys I stand corrected, OscarM is correct.

When I was on the way back from work I keep thinking about this question and I finally knew where my mistake was. To put it simple input wattage = output wattage. I have been dealing with 18650 batteries all the time and I forgot that two 18650 in series would give much higher voltage than LED Vf, so the buck driver will ‘absorb’ more voltage from the batteries but lower current draw from each battery.

In this X3 case however I forgot that it uses AA batteries, in which the total Nimh batteries voltage would be just around 3.6V, similar with the output voltage (LED Vf), so each battery would give the same 2.1A. Somemore the Nanjg 105C is a linear but not buck driver.

So back to the battery carrier resistant topic. I still think that at 2.1A current draw from each battery is still doing fine with the carrier. As from my experience with flashlight normally the resistant of all connections need to be seriously reduced when the current >3A (i.e. changing into heavier gauge of wires, copper-braiding). In addition to that with alkalines or Nimh batteries the batteries voltage will sag very quickly and you won’t stay at 2.1A for too long.

So back to the battery carrier resistant topic. I still think that at 2.1A current draw from each battery is still doing fine with the carrier. As from my experience with flashlight normally the resistant of all connections need to be seriously reduced when the current >3A (i.e. changing into heavier gauge of wires, copper-braiding). In addition to that with alkalines or Nimh batteries the batteries voltage will sag very quickly and you won’t stay at 2.1A for too long.

In other word, using AA NiMH only give a burst of high output and after that will be visibly dim compared to first switch on. maybe that’s why 3xAA is less popular than 4xAA format.
thanks bibihang for the sharing

If the batteries are in series 2,1A is drawn from each battery. (if the batteries are parallell they would be delivering 0,7A, but then you would have a voltage of 1,2V instead of 3,6V…)

i did a basic test some weeks ago with my X3 from wallbuys. I used 3 quite fresh GP recyko’s and measured 4,02V resting voltage at the battery carrier. Then i used 2 DMM, one measuring current (i think it was about 2,8A on high) and one measuring voltage under load.

-It didn’t take long for the 3 batteries in series to fall to 3,2V under load.

-So i guess that’s why i have been having problems with this flashlight when running it on high with AA’s. After a while on high it starts ramping up and down, and i’ve been wondering if that’s a low voltage warning.

-Maybe recyko’s don’t keep up their voltage under load as good as they would have needed to be used in this flashlight.

i’m going to gift this flashlight, so i’m thinking about changing driver to something easier on the batteries, maybe 1400 mA could be good enough for this flashlight in the hands of a non-flashaholic using it on AA batteries.

I stand corrected.!

Thanks OscarM

The Eneloop 2005-2022 info threadno, when you add them in series the current drawn from each battery is the same, but the voltage adds up.

so for the total of 3 batteries @ 3,6V and 2,8A every battery needs to deliver 2,8A and 1,2V

power = 3,6V * 2,8A => 10,08W

each battery provides a third of that:

1,2V * 2,8A = 3,36W

Hopefully this helps

I stand corrected.!

Thanks OscarM

The Eneloop 2005-2022 info threadHi OscarM, I think what you mean are on the output side? Let’s say a light with three LED wired in series, the current going through them is the same but the voltage is added up.

EDIT: Okay I am not an electronic guy so I don’t want to put it into calculations in case my math errors may confuse some people. So I just mention an example:

My friend has a Skyray STL-V2, as we all know it has a single XM-L powered by 2*18650 in series. With freshly charged batteries we measured about

1.4Aand 8.2V at the tail, but actually the LED receives about 3.5V and2.8Aof current.hey, cool down and think a little?

yes, we’re talking about current draw, and i included voltage and power as well.

noone has talked about capacity… (power (W) and capacity (mAh) is not the same thing)

-if you have 3 nimh AA batteries in series, you get (nominal) 3,6 V. agree?

-if those 3 batteries in series are in a flashlight that pulls 2,8A we have 3,6V and 2,8A from the batteries. agree?

-the power from the batteries is 3,6*2,8 = 10,08 W. agree?

-for 3 batteries to reach 10,08W, each battery need to deliver a third of the total power: 10,08/3 = 3,36W. agree?

-each battery has a voltage of 1,2V nominal, and to get the current when we know the power and the voltage we take divide the power by the voltage: 3,36/1,2 = 2,8.

So in series each battery has the same current drawn as the total current draw. the benefit of adding batteries in series is that you get a higher voltage.

Guys, OscarM is correct as in the formula. reference here.

So, if one buy this light merely to use with AA only to obtain maximum output (and also run time), do you guys as users recommend it?

I still dont get why there is NO proper review done on this item, there are some pre-reviews but none with full beamshots and finished :D!

http://www.benl.ebay.be/itm/2-2800mWh-AA-NiZn-1-6V-Volt-Rechargeable-Bat...

1,6 v batteries for higher voltage

Look: http://translate.google.pl/translate?sl=pl&tl=en&js=n&prev=_t&hl=pl&ie=U...

Ok sorry guys I stand corrected, OscarM is correct.

When I was on the way back from work I keep thinking about this question and I finally knew where my mistake was. To put it simple input wattage = output wattage. I have been dealing with 18650 batteries all the time and I forgot that two 18650 in series would give much higher voltage than LED Vf, so the buck driver will ‘absorb’ more voltage from the batteries but lower current draw from each battery.

In this X3 case however I forgot that it uses AA batteries, in which the total Nimh batteries voltage would be just around 3.6V, similar with the output voltage (LED Vf), so

each battery would give the same 2.1A. Somemore the Nanjg 105C is a linear but not buck driver.So back to the battery carrier resistant topic. I still think that at 2.1A current draw from each battery is still doing fine with the carrier. As from my experience with flashlight normally the resistant of all connections need to be seriously reduced when the current >3A (i.e. changing into heavier gauge of wires, copper-braiding). In addition to that with alkalines or Nimh batteries the batteries voltage will sag very quickly and you won’t stay at 2.1A for too long.

That looks like a good review, nice! Can you do some comparison beamshots with other lights, if you have?

Pitty that none of BLF’ers cared to finalise theirs :P!

In other word, using AA NiMH only give a burst of high output and after that will be visibly dim compared to first switch on. maybe that’s why 3xAA is less popular than 4xAA format.

thanks bibihang for the sharing

Anyone got the X3 from

FT?Just wondering how it compares with the one from Banggood. The driver seems to be a different one.

Lights out! That's when things get interesting...I have an X3 from FT. But I dont’t know how to check the driver.

Also what would be the best batteries to use in our X3?

Low mode and long runtime lover…

Can you fit a 32650 in there?

## Pages