I have a flat top Samsung 26FM and since I’m holding it in place, thought it would work for the test.
I get –08.7 on the 200m setting on my old light and –05.6 on the new one.
Why risk ruining 4 new cells? It’s pretty easy to measure parasitic drain. Then you know if there’s a problem or not.
I wonder if the person sold it because they knew it had a drain problem? Maybe. If the driver is bad, you can get another for $10. To swap drivers requires soldering 5 wires.
If you can’t solder, well, another option to “fix” it is to just twist the battery tube when your done using the light. This cuts all power. It won’t drain at all. This is the best way to store a light.
I think your not waiting the 5 seconds for the reading to change. On my light I initially see 5.2mA (milliamp), but then it drops to 0.11mA.
Just a note, I said the parasitic drain should be about 30μA (microamp). I was going from memory and that is with the green light turned off. With the green light turned on it’s about 130μA (0.13mA).
Usually the test probe polarity doesn’t matter for current, but if you see a negative number, just switch the leads around. It should read the same just without the minus sign. Oops, I misunderstood. Pressing against the outer driver ring is best.
So the 8.7mA drops to only 3.6mA after 5 seconds? That’s 30 times too high. Let’s see, with 4 x 3,000mah cells that’s 12,000mah ÷ 3.6mA is 3,333 hours or 138 days for it to go from 4.2v down to about 2.8v or so. Let’s say you were pretty low on power when you last used it, say 3.2v. About 30 days doesn’t seem like enough time to drain it to below 2.5v. Especially since the parasitic drain tends to drop a bit as the voltage drops. Weird, I might be off in my numbers, though. Also, the drain might vary based on what’s causing it. It might have been worse before you checked it over. Stuff like filtering capacitors can short or 7135 chips can leak. Who knows? You’d really have to trace the current leak to find the problem.