I agree, I hate charging perfect condition cells at 2 amps, I generally charge them at .5-1 amps tops. I see no reason to stress them out while charging them unless I am in a hurry. In that case I keep spare cells around for a reason.
When reviving a battery in particular though I will at most do 500ma, generally less all the way to 4.2V. Then rest the cell for a week or 2 to see if it maintains the charge before using it.
Any cell that doesn’t maintain at least 4.15v. Dropping from 4.2 to 4.15 is fairly normal after resting but much more is a no go for me unless used in a very low drain application.
At over discharged voltages the copper current collector can dissolve in the electrolyte. Then when the cell is charged the copper re deposits and can form dendrites and cause a short.
Fellows, jomertab wasn't overly prodigal on providing precise information as to what exactly he did and how. I presume he just gave the cell some very brief bursts to raise it to “some” voltage, and then he set it on the charger. I don't know what minimum voltage is required for a BT-C3100 to pump some sort of charge current for a presumed li-ion cell, probably slightly more than the maximum typical value for a Ni-MH; for the same reason, I also don't know what current does it pumps in such a case, yet my guess is “quite low”.
Unless someone can provide with some sort of wise information in this regard, I see no point in those “raise slowly” policies. Little energy is actually required to set the cell in “valid” (2.5+V) territory, so if you're willing to take the risk in recovering a cell, which can be pretty 0K if over-discharged for just a brief while, I'd just give it some little low duty cycle bursts from another cell for it to get into charger acceptable voltage territory. Or use some sort of slow, dumb chinese charger… and take cover! That's about it. :-)
sounds like he spun the cylinder one time too many…
probably a worn out junk cell that had high resistance and damage from overdischarge pushed into thermal runaway by a too high charge rate for even a new cell of that type.
i/o error.
means idiot operator.
Reading the link posted in the OP indicates that the cell was a Panasonic NCR18650 so a quality cell but I couldn’t see anywhere if it was protected or unprotected. Raising the voltage of a tripped protected cell is ok but if it was unprotected with zero voltage then trying to charge it up is in my opinion only asking for bad things to happen.
It reminds me of a coworker who used to reload 9mm by dipping the cases into powder until they were full to the brim. When I asked what powder it was he said he didn’t know and why that would matter.