Ok, need a little bit of aclaration here (quite dumb question at this level :shy: ).
Having only this info, which one is better regulated? The 2nd one?
TF 14500 prot
(black/flame)
3.55V
4.05V
LOW
0.165A
0.270A
Light nº1
MED
0.510A
0.825A
HI
0.610A
1.22A
LOW
0.115A
0.095A
Light nº2
MED
0.550A
0.480A
HI
1.33A
1.3A
And brightness not only depends on current, right? I mean, current may be higher with NiMh and lower with li-ion, but with li-ion, this it will be brighter. What was that formula to see which one will be brighter when only V and A are known?
Thanks in advance
light#2 is better regulated. the higher amperage at lower voltage can be taken as indirect sign of stabilization. check the mix6 hkj review for example.
brightness? formula? if only V and A are known, then yes you could probably do a rough calculation of W by P = U * I formula. This way you are calculating the exact wattage (W) provided by the Alkaline cell at this instance. this doesnt say anything about brightness (B) as you know unless it's the identical flashlight. even then, if W2 = W1 * 80%, of the identical torch, you cannot conclude that B2 = B1* 80%.
if i want to know the brightness of a torch, i simply compare it to a Fenix ANSI torch, such as LD01 R5 and LD20 R5.
in the end what counts is not what you got on paper (measurements and specs) but how bright your light in reality is as in visual actual human perception say your neighbor's eyes in a ceiling bounce test.
i trust my neighbor's (layman!) evaluation. if he says zebra stinks, then be it.
Yeah, that’s what I thought. Thanks for confirming that
Final A must be higher for keep the brightness at max level. Example: 4,2V * 1,3A = 5,46W. To keep the brightness at max, final current (i.e. almost dead batt) should be 5,46W / 3,4V = 1,60A , right? Of course there is no 100% efficensy driver but yeah, I got the idea Thanks again for the info
Thanks again for the info