its stated up to 6100, if it will reach that we dont know, but always take off like 20% of the lumens if u to go neutral and lower so a bit lower heat but not much… it will still get kinda hot on highest even on a WW emitters…
Heat will be the same. It should draw the same amps, just put out less lumens (typically speaking, it depends on led bin) Usually NW and WW have lower bin outputs, but 20% lower seems a bit too much. We really don’t know what led bins they will be using.
We probably won’t know until they are sold and tested.
But it’s not just NW vs WW. The 4000K is 95CRI whereas the 5000K is 70CRI. The lumen output will likely be 30+% lower on the 4000K version would be my guess.
Some people managed to drive the SST-20’s in their Fireflies E07 blue by using high drain 21700’s, hence the question. But I guess the 26650 Shockli will be fine.
There’s more than one bin and we don’t know which is being used. How are you predicting the amperage?
Are you aware those led tests are raw led, no optics?
Are you aware the light that measured 6100 lumen is actually rated at 5500 lumen? We don’t even know the time or temperature of the led when it was measured. We don’t know the rig used to measure it.
You know the output will change based on the battery used, right?
We don’t have anywhere near enough info to be making predictions, at least with any decent accuracy.
Maybe we can extrapolate some info based on the Fireflies E07. It seems to be pretty similar. There still might be differences in the driver. Unfortunately, I don’t know much about that light.
1. i shure they will use the most prevalent led bins but not high efficiency bins what are comparatively rare.
2. raw led, no optics=yes values of light loss in the integrative sphere and the optics are of the same order.
3. 6100 = max light according to the manufacturer’s measurments on COLD leds w/o battery drain limit. imho there is 2.3-2.6 amps/led.
of course we are talking about values with some approximation, I would say 8-10%. I think that the manufacturer himself does not know the values that will be in the mass product.
Definitely not. Typical optics or reflector and lens means about a 20–25 loss in output compared to a raw led. Both use an integrating sphere so that is not a factor.
